36x^2-36x-13=0

Solution for 36x^2-36x-13=0 equation:

36x^2-36x-13=0

a = 36; b = -36; c = -13;
Δ = b2-4ac
Δ = -362-4·36·(-13)
Δ = 3168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3168}=\sqrt{144*22}=\sqrt{144}*\sqrt{22}=12\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-12\sqrt{22}}{2*36}=\frac{36-12\sqrt{22}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+12\sqrt{22}}{2*36}=\frac{36+12\sqrt{22}}{72}
$